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Half Life Decay Equation. During the next 3 years, 12.5 grams would remain and so on. (1) n t = n 0e−λt, where.
Applications of First Order Differential Equations from www.youtube.com
We can use the equation to derive an equation for half life. N t is the quantity at time t. E is the euler’s number equal to 2.71828.
Applications of First Order Differential Equations
Half life = [ time • ln (2) ] ÷ ln (beginning amount ÷ ending amount) half life = [ 11 •.69315 ] ÷ ln (326.04 ÷ 126) half life = [ 15.870 ] ÷ ln (2.5876) We will replace t with in the equation, so: \(t\frac{1}{2}\) = 0.693/ λ \(t\frac{1}{2}\) = 0.693/0.002 = 346.5. So we can substitute this value in for y y y, and then simplify the decay formula.